Standard Deviation Examples

In this class, We discuss Standard Deviation Examples.

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Example 1:

The below table shows the data and values needed to find the standard deviation.

Standard Deviation Examples 1
Example 1

Column Xi shows the data values.

The column Fi shows the frequency values.

First, we need to find the mean value given frequencies.

We find XiFi and use the values to find the arithmetic mean.

Arithmetic mean = X’ = ΣXiFi/ΣFi = 760/40 = 19

N = ΣFi = 40

we find the Fi(Xi – X’)^2 for standard deviation.

Standard Deviation = σ = √1/N Σ fi (Xi – X’)^2

σ^2 = 1736/40

σ = √43.4 = 6.58

Example 2:

X1′, σ1be mean and standard deviation of size n1

X2′, σ2 be mean and standard deviation of size n2.

Find the mean and standard deviation of the combined sample n1 + n2?

Solution:

X’ = combined sample mean = (n1x1′ + n2x2′)/(n1 + n2)

The equation of combined arithmetic mean explained here.

combined standard deviation = σ = √(n1σ1^2 + n2σ2^2 + n1D1^2 + n2D2^2)/(n1+n2)

D1 = X1′ – X’

D2 = X2′ – X’

Example:

The below table shows the mean and standard deviation of three data samples.

Standard Deviation Examples 2
Example 2

Mean = X’ = (n1x1′ + n2x2′ + n3X3′)/(n1 + n2+ n3)

Substituting the values we get X’ = (50 * 113 + 60 * 120 + 90 * 115)/ (50 + 60 + 90)

X’ = 116

D1 = X1′ – X’ = 113 – 116 = -3

D2 = X2′ – X’ = 120 – 114 = 6

D3 = X3′ – X’ = 115 – 116 = -1

combined standard deviation = σ = √(n1σ1^2 + n2σ2^2 + n3σ3^2 + n1D1^2 + n2D2^2 + n3D3^2)/(n1+n2 + n3)

σ = 7.746