Examples on Ages 2
In this class, We discuss Examples on Ages 2.
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Example 1:
Rohith was four times as old as his son eight years ago.
After eight years, Rohith will be twice as old as his son. What are their present ages?
Solution:
Let sons age eight years ago be x.
Rohith’s age was eight years ago is 4x.
Sons age after eight years is x+8+8
= x + 16
Rohit’s age after eight years is 4x + 16
2(x+16) = 4x+16
x = 8
son age = x+8 = 16
Rohit age = 4x+8 = 40
Example 2:
Abhay’s age after six years will be 3/7th of his father’s age.
Ten years ago, the ratio of their ages was 1: 5
What is Abhay’s father’s age today?
Solution:
The ratio of Abhay and their father’s age ten years ago is x: 5x
Abhay age after six years = (x+10) + 6
Father age after six years = (5x + 10) +6
x+16 = 3/7(5x+16)
8x = 64
x = 8
Father present age = 5x+10 = 50